NCERT Solutions for Class 12 Chemistry Chapter 10Biomolecules (English Medium)

🧬 Get NCERT Solutions for Class 12 Chemistry Chapter 10 – Biomolecules with accurate answers and step-by-step explanations in an exam-friendly format. This chapter covers carbohydrates (mono/di/polysaccharides, glycosidic bond), proteins (amino acids, peptide bond, primary/secondary/tertiary structure, denaturation), enzymes, vitamins (A, B-complex, C, D, E, K), nucleic acids (DNA, RNA, nucleoside, nucleotide), and key biological functions in a simple, scoring way. Perfect for CBSE boards and NEET/JEE revision. ✅

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NCERT Solutions for Class 12 Chemistry Chapter 10 – Biomolecules
Showing all questions
Q.1: What are monosaccharides?
Answer ✅
Monosaccharides are the simplest carbohydrates (single sugar units) that cannot be hydrolysed into smaller carbohydrates.

They are the basic building blocks of di-, oligo- and polysaccharides.

Examples: glucose, fructose, ribose.
Explanation (Step by Step) 👉
“Mono” means one and “saccharide” means sugar.

• So a monosaccharide is a single carbohydrate unit.

• They usually have the general formula (CH2O)n (commonly n = 3 to 7).

• Monosaccharides contain a carbonyl group (aldehyde or ketone) and multiple –OH groups, which is why they are sweet and water soluble.
Did You Know? 🤔📌
Glucose is called blood sugar because it is the main sugar carried in human blood.

Ribose and deoxyribose are monosaccharides that form the sugar part of RNA and DNA.
Q.2: What are reducing sugars?
Answer ✅
Reducing sugars are carbohydrates that can reduce mild oxidising agents like Tollens’ reagent or Fehling’s solution because they have a free aldehyde group (–CHO) or can form one in solution.

Examples: glucose, fructose, maltose, lactose.
Non-reducing example: sucrose.
Explanation (Step by Step) 👉
1) What “reducing” means here
A sugar is called “reducing” if it can donate electrons and reduce:

• Tollens’ reagent: Ag+ → Ag (silver mirror)
• Fehling’s solution: Cu2+ → Cu2O (red precipitate)

2) Why they can reduce these reagents
✅ Reducing sugars have a free anomeric carbon (the carbonyl carbon in open-chain form).

Aldoses (like glucose) have –CHO directly.

Some ketoses (like fructose) still act reducing because in basic medium they tautomerise to an aldehyde form.

✅ If the anomeric carbon is tied up in a glycosidic bond (like in sucrose), the sugar can’t open up to give a free carbonyl group → non-reducing.
Did You Know? 🤔📌
✅ All monosaccharides are reducing sugars (they have a free anomeric carbon).

Sucrose is non-reducing because both anomeric carbons (of glucose and fructose) are involved in the glycosidic bond, so no free –CHO can form.
Q.3: Write two main functions of carbohydrates in plants.
Answer ✅
✅ Two main functions of carbohydrates in plants are:

1) Energy storage: Plants store carbohydrates mainly as starch, which is used as an energy reserve.

2) Structural support: Carbohydrates form cellulose in plant cell walls, providing strength and rigidity.
Explanation (Step by Step) 👉
Starch is the plant’s “food bank”. During growth, respiration, or when sunlight is not available, plants break starch into glucose to release energy.

Cellulose is the main material of plant cell walls. It acts like a strong framework that helps plants stay upright and protects cells.
Did You Know? 🤔📌
Starch and cellulose are both made of glucose, but their linkages are different, so:

humans can digest starch easily,
but humans cannot digest cellulose (it acts as dietary fibre).
Q.4: Classify the following into monosaccharides and disaccharides: Ribose, 2-deoxyribose, maltose, galactose, fructose and lactose.
Answer ✅
Monosaccharides (single sugar unit)

Ribose
2-deoxyribose
Galactose
Fructose

Disaccharides (two sugar units)

Maltose
Lactose
Explanation (Step by Step) 👉
Monosaccharides are the simplest sugars that cannot be broken into smaller sugars (example: ribose, fructose).

Disaccharides are made by joining two monosaccharides through a glycosidic bond (example: maltose, lactose).
Did You Know? 🤔📌
Ribose is found in RNA, while 2-deoxyribose is found in DNA.

Lactose is “milk sugar”, and maltose is “malt sugar” formed during starch breakdown.
Q.5: What do you understand by the term glycosidic linkage?
Answer ✅
✅ A glycosidic linkage is the bond formed between two monosaccharide units through an oxygen atom (–O–).
Explanation (Step by Step) 👉
• It is formed by a condensation reaction between the –OH groups of two monosaccharides.

• During bond formation, one molecule of water (H2O) is released.

• The resulting bond is an O-glycosidic bond that joins the sugars into a disaccharide or polysaccharide.

✅ Example (sucrose):
Glucose + FructoseSucrose (joined by a glycosidic linkage) + H2O
Did You Know? 🤔📌
✅ The type of glycosidic linkage (like α-1,4 or β-1,4) decides the properties of carbohydrates.

Example: starch (α-linkage) is digestible, but cellulose (β-linkage) is not easily digested by humans.
Q.6: What is glycogen? How is it different from starch?
Answer ✅
Glycogen is a storage polysaccharide in animals, mainly stored in the liver and muscles (also found in small amount in brain). When the body needs energy, glycogen is broken down to glucose.

✅ Difference from starch: Starch is the storage polysaccharide in plants, while glycogen is the storage polysaccharide in animals.
Explanation (Step by Step) 👉
1) Where they are stored
Glycogen: stored in animals (liver, muscles)

Starch: stored in plants (seeds, roots, tubers like potato)

2) Composition
Starch is a mixture of:

Amylose (15–20%): mostly unbranched, relatively more soluble
Amylopectin (80–85%): branched, less soluble

Glycogen is a branched polymer of α-D-glucose (single main type, but highly branched).

3) Branching (main chemical difference)
✅ Both glycogen and amylopectin are branched, but:

Glycogen is more highly branched than amylopectin.

Amylopectin has longer branch segments (about 20–25 glucose units)
Glycogen has shorter branch segments (about 10–14 glucose units)
Did You Know? 🤔📌
✅ Because glycogen is highly branched, it can be broken down very quickly to release glucose when the body suddenly needs energy (like during running or exercise).

Amylose has mainly C1–C4 glycosidic links, while branching in amylopectin and glycogen occurs through C1–C6 links.
Q.7: What are the hydrolysis products of (i) sucrose and (ii) lactose?
Answer ✅
(i) Sucrose molecule on hydrolysis gives one molecule of 𝛼– D-(+)- glucose and one molecule of β-D- (-) -fructose.

(ii) Lactose on hydrolysis gives β-D-(+)- galactose and β-D-(+)-glucose.
Explanation (Step by Step) 👉
Hydrolysis breaks the glycosidic linkage of a disaccharide using water (often with acid or enzymes).

• So each disaccharide splits into its two monosaccharide units:

Sucrose + H2O → 𝛼– D-(+)- glucose + β-D- (-) -fructose

Lactose + H2O → β-D-(+)- galactose + β-D-(+)-glucose
Did You Know? 🤔📌
✅ Hydrolysis of sucrose gives an equimolar mixture of glucose and fructose called invert sugar (it rotates plane-polarized light in the opposite direction compared to sucrose).

Lactose is called milk sugar, and many people have lactase enzyme deficiency, causing lactose intolerance.
Q.8: What is the basic structural difference between starch and cellulose?
Answer ✅
✅ The basic structural difference is the type of glycosidic linkage between glucose units:

Starch has α-glycosidic linkages (mainly α-1,4 and α-1,6).

Cellulose has β-glycosidic linkages (β-1,4).
Explanation (Step by Step) 👉
Both starch and cellulose are polymers of D-glucose, but the orientation of the linkage is different.

Starch

α-1,4 linkage in amylose (mostly straight/helix)
α-1,6 branching in amylopectin (branched)

Cellulose

β-1,4 linkage throughout (straight, rigid chains)

👉 These straight chains align and form strong hydrogen bonding, making cellulose tough.
Did You Know? 🤔📌
✅ Humans can digest starch because we have enzymes that break α-linkages.

✅ Humans cannot digest cellulose because we lack the enzyme to break β-1,4 linkages (so cellulose acts as dietary fibre).
Q.9: What happens when D-glucose is treated with the following reagents?
(i) HI
(ii) Bromine water
(iii) HNO3
Answer ✅
(i) With HI
✅ D-glucose is reduced and on prolonged heating with excess HI (often with red phosphorus), it gives n-hexane.
👉 Product: n-hexane (C6H14)
(ii) With bromine water
✅ Bromine water (a mild oxidising agent) oxidises only the aldehyde group (–CHO) of glucose to carboxylic acid.
👉 Product: D-gluconic acid (C6H12O7)
(iii) With HNO3
✅ Concentrated nitric acid oxidises both the aldehyde group (–CHO) and the primary alcohol group (–CH2OH) to carboxylic acids.
👉 Product: D-saccharic acid (glucaric acid), a dicarboxylic acid
Explanation (Step by Step) 👉
(i) HI

• HI is a strong reducing agent.
• It replaces oxygen-containing groups step by step and finally converts glucose into a straight-chain hydrocarbon.
✅ Hence: glucose → n-hexane

(ii) Bromine water

• Bromine water is mild, so it oxidises only –CHO (not –CH2OH).
✅ Hence: glucose (aldose) → gluconic acid

(iii) HNO3

• Nitric acid is strong, so it oxidises both ends of glucose:

–CHO → –COOH
–CH2OH → –COOH

✅ Hence: glucose → saccharic (glucaric) acid
Did You Know? 🤔📌
✅ The bromine water reaction is used to show that glucose contains an aldehyde group, because it forms gluconic acid without breaking the carbon chain.

✅ Strong oxidation with HNO3 gives a dicarboxylic acid, which proves glucose has a primary alcohol group at one end.
Q.10: Enumerate the reactions of D-glucose which cannot be explained by its open chain structure.
Answer ✅
The following reactions of D-glucose cannot be explained by its open chain (aldehyde) structure:

1) Glucose does not give usual aldehyde tests
✅ Even though glucose is expected to have an –CHO group, it:
👉 does not give 2,4-DNP test
👉 does not give Schiff’s test
👉 does not form an addition product with NaHSO3

2) Glucose pentaacetate does not react with hydroxylamine (NH2OH)
✅ If a free –CHO group were present, it should form an oxime, but it does not.

3) Glucose forms α- and β-methyl glucosides with methanol + dry HCl
✅ D-glucose + CH3OH (dry HCl) gives two glucosides (α and β), which is possible only if glucose exists mainly in a cyclic (ring) form.
Explanation (Step by Step) 👉
👉 If glucose were purely open-chain aldehyde, it should show typical aldehyde reactions (2,4-DNP, Schiff, NaHSO3 addition) and should form oxime from pentaacetate.

👉 But these reactions fail, and glucose instead forms α/β glucosides, which strongly suggests that glucose exists mainly as a hemiacetal ring in solution (so the free –CHO is not readily available).
Did You Know? 🤔📌
✅ In water, D-glucose exists mostly in cyclic forms (α and β anomers), and only a very small amount is in the open-chain form. That’s why many “aldehyde-type” reactions are weak or absent.
Q.11: What are essential and non-essential amino acids? Give two examples of each type.
Answer ✅
Essential amino acids: Amino acids needed for normal growth and health but cannot be synthesised by the human body, so they must be obtained from diet.
👉 Examples: valine, leucine

Non-essential amino acids: Amino acids that are also needed by the body but can be synthesised in the body, so they may not be required in diet in sufficient amounts.
👉 Examples: glycine, alanine
Explanation (Step by Step) 👉
Our body needs amino acids to build proteins, enzymes, and tissues.

Some amino acids cannot be made in the body (essential), so we must eat them.

Some amino acids can be made by the body from other nutrients (non-essential).
Did You Know? 🤔📌
✅ Foods like milk, eggs, fish, pulses/soybean are good sources of essential amino acids.

✅ The word “non-essential” does not mean unimportant; it only means the body can make them.
Q.12: Define the following as related to proteins:
(i) Peptide linkage
(ii) Primary structure
(iii) Denaturation
Answer ✅
(i) Peptide linkage
✅ A peptide linkage (peptide bond) is the –CO–NH– bond formed when the –COOH group of one amino acid reacts with the –NH2 group of another amino acid, with loss of one H2O molecule.
(ii) Primary structure
✅ The primary structure of a protein is the exact sequence and number of amino acids linked in a polypeptide chain.
👉 Even a small change in this sequence can produce a different protein.
(iii) Denaturation
✅ Denaturation is the process in which a protein loses its native (natural) shape and hence loses biological activity, due to disturbance of bonds (mainly hydrogen bonds).
👉 It can be caused by heat, change in pH, etc.

✅ During denaturation, secondary (2°) and tertiary (3°) structures are destroyed, but the primary (1°) structure remains.
Explanation (Step by Step) 👉
(i) Peptide linkage (how it forms)

👉 Amino acid 1 (–COOH) + Amino acid 2 (–NH2)
–CO–NH– + H2O
This is a condensation reaction.

(ii) Primary structure (why important)

👉 It tells which amino acids are present
👉 In what order they are arranged

✅ This sequence controls the final folding and function of the protein.

(iii) Denaturation (what changes)

👉 Heat/pH breaks H-bonds and weak interactions
👉 Protein unfolds (globular proteins lose shape; helices uncoil)

✅ Function is lost because shape decides function.

Example: boiling an egg causes coagulation of egg protein (albumin).
Did You Know? 🤔📌
✅ Denaturation usually cannot be reversed (like boiled egg), but in some cases it can be partially reversible if mild conditions are used.

✅ That’s why high fever can affect enzyme activity, because enzymes are proteins and can denature at high temperature.
Q.13: What are the common types of secondary structure of proteins?
Answer ✅
✅ The most common secondary structures of proteins are:

1. α-helix
2. β-pleated sheet
Explanation (Step by Step) 👉
✅ Secondary structure refers to the shape of the polypeptide chain formed mainly due to hydrogen bonding between groups in the peptide backbone (not between side chains).

1) α-Helix

• The polypeptide chain coils into a right-handed helix.
• ✅ A hydrogen bond forms between:
👉 C=O of one amino acid and N–H of the amino acid four units ahead in the chain.
• The R-groups (side chains) project outward, so they can interact easily.

2) β-Pleated Sheet

• The polypeptide chains are stretched out and arranged side by side.
• ✅ They are held together by intermolecular hydrogen bonds between:
👉 C=O and N–H groups of adjacent chains/segments.
• The sheet looks like folds (pleats), and the R-groups extend above and below the sheet.
Did You Know? 🤔📌
Hydrogen bonding is the main force that stabilizes secondary structures.

✅ Materials like hair and nails (keratin) have a lot of α-helix, while silk (fibroin) is rich in β-pleated sheets, which is why silk is strong and flexible.
Q.14: What type of bonding helps in stabilising the α-helix structure of proteins?
Answer ✅
✅ The α-helix structure of proteins is stabilised by intramolecular hydrogen bonding.
Explanation (Step by Step) 👉
👉 In an α-helix, the polypeptide chain coils like a spring.

✅ A hydrogen bond forms between:

👉 the C=O (carbonyl oxygen) of one amino acid residue and the N–H (amide hydrogen) of the fourth amino acid residue ahead in the same chain.

👉 Since these H-bonds are within the same chain, they are called intramolecular H-bonds.

✅ These repeated H-bonds hold the helix tightly and make it stable.
Did You Know? 🤔📌
✅ If temperature becomes too high or pH changes a lot, hydrogen bonds can break and the helix may unwind, leading to denaturation of the protein.
Q.15: Differentiate between globular and fibrous proteins.
Answer ✅
Globular proteins are spherical and water soluble, mainly involved in biological functions like enzymes and hormones. Example: Insulin, Albumin, Haemoglobin.

Fibrous proteins are long, thread-like and insoluble, mainly used for structural support like hair, skin, and tendons. Example: Keratin (present in hair, wool, silk), Myosin (present in muscles), etc.
Explanation (Step by Step) 👉
1) Shape
Globular: compact, rounded/spherical
Fibrous: elongated, rod-like or thread-like

2) Solubility
Globular: generally soluble in water (or aqueous solutions)
Fibrous: generally insoluble in water

3) Main role
Globular: functional proteins (do active jobs in the body)
✅ Examples: enzymes, hemoglobin, insulin, antibodies

Fibrous: structural proteins (give strength and support)
✅ Examples: keratin (hair, nails), collagen (connective tissue), fibroin (silk)
4) Level of structure
Globular: usually have strong tertiary (3°) structure (often also quaternary)
Fibrous: mainly have secondary (2°) structure (repeating pattern), less complex folding
Did You Know? 🤔📌
✅ The reason globular proteins dissolve more is that their outer surface often has polar (hydrophilic) amino acids, which interact well with water.

✅ Fibrous proteins have more hydrophobic packing and strong cross-linking, which makes them tough and insoluble.
Q.16: How do you explain the amphoteric behaviour of amino acids?
Answer ✅
✅ Amino acids show amphoteric behaviour because they contain both an acidic group –COOH and a basic group –NH2 in the same molecule. So, they can act as acid as well as base.
Explanation (Step by Step) 👉
1) Formation of zwitterion (dipolar ion) in water
In aqueous solution, the –COOH group donates H+ and the –NH2 group accepts H+:

👉 H2N–CH(R)–COOH ⇌ H3N+–CH(R)–COO

✅ This is called a zwitterion (overall neutral but has both + and charges).
2) Why they act as both acid and base
✅ In acidic medium:
The –COO part accepts H+ → acts as a base.

✅ In basic medium:
The –NH3+ part donates H+ → acts as an acid.

👉 इसलिए amino acids amphoteric होते हैं (both acidic + basic nature).
Did You Know? 🤔📌
✅ Because amino acids exist mainly as zwitterions, they have high melting points and are usually soluble in water.

✅ At a particular pH (isoelectric point), amino acids exist mostly as zwitterions and show minimum movement in an electric field.
Q.17: What are enzymes?
Answer ✅
Enzymes are proteins that act as biological catalysts. They speed up biochemical reactions in living organisms without being consumed.
Explanation (Step by Step) 👉
1) Specific nature of enzymes
Enzymes are highly specific, meaning one enzyme usually works on a particular substrate and catalyses a specific reaction.
2) Small amount + reuse
They are needed in very small amounts because they can be used again and again.
3) Optimum temperature and pH
Enzymes work best at an optimum temperature (about 310 K in the human body) and an optimum pH (around 7.4 for many blood enzymes).
4) Example
Example:
👉 Maltase catalyses the hydrolysis of maltose into glucose.
Did You Know? 🤔📌
✅ Many enzymes are named by adding “-ase” to the substrate or reaction type:

Maltase (acts on maltose)
Lipase (breaks fats/lipids)
Protease (breaks proteins)

✅ If temperature or pH goes far from the optimum, enzymes can denature and stop working properly.
Q.18: What is the effect of denaturation on the structure of proteins?
Answer ✅
Denaturation destroys the native 3D structure of proteins. It breaks the forces holding the folded shape, so the protein unfolds and loses biological activity, while the primary structure remains unchanged.
Explanation (Step by Step) 👉
1) Which structures get affected
Secondary (2°), tertiary (3°) and quaternary (4°) structures are destroyed because denaturation breaks:

👉 hydrogen bonds
👉 ionic interactions
👉 hydrophobic interactions

Primary (1°) structure remains intact because peptide bonds are not broken (amino acid sequence stays the same).
2) What happens to the protein shape
👉 Globular proteins often unfold into a more random, thread-like form.

👉 Many proteins become less soluble and may coagulate/precipitate.
3) Functional effect
✅ Since shape controls function, denaturation causes proteins (especially enzymes) to lose their biological activity.
Did You Know? 🤔📌
✅ The classic example is boiling an egg: egg protein (albumin) denatures and coagulates, turning from clear to white.

Extreme heat or big pH change can denature enzymes, which is why enzymes work best only in a narrow temperature and pH range.
Q.19: How are vitamins classified? Name the vitamin responsible for the coagulation of blood.
Answer ✅
✅ Vitamins are classified into two groups based on solubility:

1) Fat-soluble vitamins: A, D, E, K
2) Water-soluble vitamins: B-complex and C

✅ The vitamin responsible for blood coagulation (clotting) is Vitamin K.
Explanation 🤔
👉 Fat-soluble vitamins (A, D, E, K) dissolve in fats and can be stored in the liver and body fat, so they don’t need to be taken daily in large amounts.
👉 Water-soluble vitamins (B-complex, C) dissolve in water and are not stored much in the body, so they are usually needed regularly through diet.
👉 Vitamin K helps in the formation of important clotting factors in the liver, so it plays a key role in stopping bleeding.
Did You Know? 🤔📌
✅ A deficiency of Vitamin K can lead to delayed blood clotting and excessive bleeding.

Green leafy vegetables (like spinach) are a common dietary source of Vitamin K.
Q.20: Why are vitamin A and vitamin C essential to us? Give their important sources.
Answer ✅
Vitamin A is essential for good vision (especially in dim light) and for keeping skin and body tissues healthy.

Vitamin C is essential for healthy gums and connective tissues (collagen formation) and helps prevent scurvy.
Explanation (Step by Step) 👉
(1) Vitamin A (Retinol)
🤔 Why essential:
👉 Helps in vision, especially night vision
👉 Maintains healthy skin and mucous membranes
👉 Supports immunity

Deficiency disease:
👉 Night blindness (and severe deficiency can cause eye problems like xerophthalmia)

Important sources:
Fish liver oil, carrots, butter, milk, eggs, green leafy vegetables (spinach)
2) Vitamin C (Ascorbic acid)
Why essential:
👉 Needed for collagen synthesis (skin, gums, wound healing)
👉 Helps immune defence
👉 Prevents bleeding gums and weakness

Deficiency disease:
👉 Scurvy

Important sources:
Citrus fruits (orange, lemon), amla, green leafy vegetables, strawberries, capsicum/pepper
Did You Know? 🤔📌
Amla is one of the richest natural sources of vitamin C and is very common in India.

Vitamin C is water-soluble and can be destroyed by overcooking, so fresh fruits/vegetables give the best benefit.
Q.21: What are nucleic acids? Mention their two important functions.
Answer ✅
Nucleic acids are biomolecules made of nucleotides (phosphate + pentose sugar + nitrogen base). They are the genetic material of living organisms.

The two main nucleic acids are DNA and RNA.
Explanation (Step by Step) 👉
Two important functions
1) Storage and transfer of genetic information
DNA stores hereditary information and passes it from one generation to the next (and from one cell to daughter cells).
2) Protein synthesis (making proteins)
RNA helps in protein formation:

👉 mRNA carries the message from DNA
👉 tRNA brings amino acids
👉 rRNA forms ribosomes where proteins are made
Did You Know? 🤔📌
✅ A nucleotide has 3 parts: phosphate + sugar (ribose/deoxyribose) + nitrogen base.

DNA is mainly in the nucleus, while different RNAs work mostly in the cytoplasm during protein synthesis.
Q.22: What is the difference between a nucleoside and a nucleotide?
Answer ✅
Nucleoside: Nitrogenous base + Pentose sugar (ribose or deoxyribose)

Nucleotide: Nitrogenous base + Pentose sugar + Phosphate group
Explanation (Step by Step) 👉
📌 Formation concept
📌 A nucleoside is formed when a base attaches to a sugar.

👉 Example: adenosine = adenine + ribose
• A nucleotide is formed when one or more phosphate groups attach to the nucleoside.

👉 Example: AMP = adenosine + phosphate

✅ So, the main difference is the phosphate group:

• No phosphatenucleoside
Phosphate presentnucleotide
Did You Know? 🤔📌
Nucleotides are the building blocks of DNA and RNA.

✅ Some nucleotides also act as energy molecules, like ATP (adenosine triphosphate), the “energy currency” of cells.
Q.23: The two strands in DNA are not identical but are complementary. Explain.
Answer ✅
✅ The two DNA strands are not identical because their base sequences are different, but they are complementary because bases pair in a fixed way:

👉 A pairs with T and G pairs with C.
Explanation (Step by Step) 👉
1) Specific base pairing rule
DNA has four bases: A, T, G, C.

They pair only like this:

A (adenine) with T (thymine) via two hydrogen bonds
G (guanine) with C (cytosine) via three hydrogen bonds

✅ So, if one strand has A at a position, the other must have T there, and if one has G, the other must have C.
2) Example shows “complementary, not identical”
If one strand is:
👉 5′–A T G C–3′

Then the other must be:
👉 3′–T A C G–5′

✅ The sequences are different, so strands are not identical.
✅ But each base is the correct partner, so they are complementary.
3) Why this matters
✅ Complementarity allows each strand to act as a template during DNA replication, helping make an exact copy of genetic information.
Did You Know? 🤔📌
✅ One reason A–T and G–C pairing is so strict is size matching:

A and G are purines (larger)
T and C are pyrimidines (smaller)

So pairing is always one purine + one pyrimidine, keeping DNA width uniform.
Q.24: Write the important structural and functional differences between DNA and RNA.
Answer ✅
DNA is the main genetic material that stores hereditary information, while RNA mainly helps in protein synthesis.
Explanation 👉
Category Point DNA RNA
A) Structural differences Sugar Has deoxyribose sugar Has ribose sugar
Strands Usually double-stranded (double helix) Usually single-stranded
Nitrogen bases A, G, C, T (thymine) A, G, C, U (uracil) (U replaces T)
Stability More stable (good for long-term storage) Less stable and more reactive (short-lived)
B) Functional differences Main role Stores and transmits genetic information; can replicate Helps in making proteins (expressing genetic information)
Types One main type (genetic store) Three major functional types:
mRNA (message)
tRNA (brings amino acids)
rRNA (forms ribosomes)
Location (general) Mainly in nucleus (also mitochondria) Made in nucleus but works mostly in cytoplasm (ribosomes)
Did You Know? 🤔📌
RNA is so important that some viruses (like many common disease-causing viruses) use RNA as their genetic material instead of DNA.
Q.25: What are the different types of RNA found in the cell?
Answer ✅
✅ Cells mainly have three types of RNA:

mRNA (messenger RNA)
tRNA (transfer RNA)
rRNA (ribosomal RNA)
Explanation (Step by Step) 👉
1) mRNA (messenger RNA)
Carries the genetic message from DNA to the ribosomes.

Works like a blueprint for making proteins.
2) tRNA (transfer RNA)
Brings specific amino acids to the ribosome.

Matches amino acids according to the codons on mRNA.
3) rRNA (ribosomal RNA)
Forms the main part of ribosomes.

Helps in proper protein assembly (structural + catalytic role).
Did You Know? 🤔📌
✅ Ribosomes are made of rRNA + proteins, and rRNA is the most abundant RNA in most cells.
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